exclude hidden users from ajax search

This commit is contained in:
imperosol
2025-11-09 21:19:15 +01:00
parent cb6fe18916
commit 59d8d73c88
6 changed files with 55 additions and 8 deletions

View File

@@ -3,6 +3,7 @@ from datetime import timedelta
import pytest
from django.conf import settings
from django.contrib import auth
from django.contrib.auth.models import Permission
from django.core.management import call_command
from django.test import Client, RequestFactory, TestCase
from django.urls import reverse
@@ -18,7 +19,7 @@ from core.baker_recipes import (
subscriber_user,
very_old_subscriber_user,
)
from core.models import Group, User
from core.models import AnonymousUser, Group, User
from core.views import UserTabsMixin
from counter.baker_recipes import sale_recipe
from counter.models import Counter, Customer, Refilling, Selling
@@ -368,3 +369,38 @@ class TestRedirectMe:
def test_promo_has_logo(promo):
user = baker.make(User, promo=promo)
assert user.promo_has_logo()
@pytest.mark.django_db
class TestUserQuerySetViewableBy:
@pytest.fixture
def users(self) -> list[User]:
return [
baker.make(User),
subscriber_user.make(),
subscriber_user.make(is_viewable=False),
]
def test_admin_user(self, users: list[User]):
user = baker.make(
User,
user_permissions=[Permission.objects.get(codename="view_hidden_user")],
)
viewable = User.objects.filter(id__in=[u.id for u in users]).viewable_by(user)
assert set(viewable) == set(users)
@pytest.mark.parametrize(
"user_factory", [old_subscriber_user.make, subscriber_user.make]
)
def test_subscriber(self, users: list[User], user_factory):
user = user_factory()
viewable = User.objects.filter(id__in=[u.id for u in users]).viewable_by(user)
assert set(viewable) == {users[0], users[1]}
@pytest.mark.parametrize(
"user_factory", [lambda: baker.make(User), lambda: AnonymousUser()]
)
def test_not_subscriber(self, users: list[User], user_factory):
user = user_factory()
viewable = User.objects.filter(id__in=[u.id for u in users]).viewable_by(user)
assert not viewable.exists()