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Allow to subscribe before subscription end

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This commit is contained in:
Pierre Brunet
2017-09-04 11:25:28 +02:00
parent 53696b7750
commit 2f912a197c
5 changed files with 36 additions and 7 deletions
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11
subscription/models.py
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@ -64,7 +64,7 @@ class Subscription(models.Model):
def clean(self):
try:
for s in Subscription.objects.filter(member=self.member).exclude(pk=self.pk).all():
if s.is_valid_now():
if s.is_valid_now() and s.subscription_end - timedelta(weeks=settings.SITH_SUBSCRIPTION_END) > date.today():
raise ValidationError(_("You can not subscribe many time for the same period"))
except: # This should not happen, because the form should have handled the data before, but sadly, it still
# calls the model validation :'(
@ -138,7 +138,7 @@ class Subscription(models.Model):
return 'No user - ' + str(self.pk)
@staticmethod
def compute_start(d=None, duration=1):
def compute_start(d=None, duration=1, user=None):
"""
This function computes the start date of the subscription with respect to the given date (default is today),
and the start date given in settings.SITH_START_DATE.
@ -150,12 +150,14 @@ class Subscription(models.Model):
"""
if not d:
d = date.today()
if user is not None and user.subscriptions.exists():
d = user.subscriptions.last().subscription_end
if duration <= 2: # Sliding subscriptions for 1 or 2 semesters
return d
return get_start_of_semester(d)
@staticmethod
def compute_end(duration, start=None):
def compute_end(duration, start=None, user=None):
"""
This function compute the end date of the subscription given a start date and a duration in number of semestre
Exemple:
@ -166,7 +168,8 @@ class Subscription(models.Model):
2015-09-18 - 4 -> 2017-09-18
"""
if start is None:
start = Subscription.compute_start(duration=duration)
start = Subscription.compute_start(duration=duration, user=user)
# This can certainly be simplified, but it works like this
try:
return start.replace(month=int(round((start.month - 1 + 6 * duration) % 12 + 1, 0)),